Решите уравнение (x^2-1)/2-(3x-1)/4=2.

\[\frac{x^{2} - 1}{2} - \frac{3x - 1}{4} = 2\ \ \ \ \ \ | \cdot 4\]

\[2 \cdot \left( x^{2} - 1 \right) - 3x + 1 - 8 = 0\]

\[2x^{2} - 2 - 3x - 7 = 0\]

\[2x^{2} - 3x - 9 = 0\ \]

\[D = 9 + 72 = 81\]

\[x_{1} = \frac{3 + 9}{4} = 3;\ \ \ \]

\[x_{2} = \frac{3 - 9}{4} = - \frac{6}{4} = - 1,5\]

\[Ответ:x = - 1,5;\ \ x = 3.\]