Решите уравнение: x^2-11x-42=0.

\[x² - 11x - 42 = 0\ \]

\[D = 121 + 168 = 289\]

\[x_{1,2} = \frac{11 \pm 17}{2}\]

\[x_{1} = \frac{28}{2} = 14;\ \ \ \ x_{2} = \frac{- 6}{2} = - 3\]