Решите уравнение: x^2+x=0.

\[10x² + 5x - 0,6 = 0\]

\[D = b^{2} - 4ac =\]

\[= 25 - 4 \cdot 10 \cdot ( - 0,6) =\]

\[= 25 + 24 = 49\]

\[x_{1} = \frac{- 5 + 7}{20} = \frac{2}{20} = \frac{1}{10} = 0,1\]

\[x_{2} = \frac{- 5 - 7}{20} = - \frac{12}{20} = \frac{6}{10} =\]

\[= - 0,6\]

\[Ответ:\ \ x = 0,1\ \ и\ \ \ x = - 0,6.\]