Решите уравнение: x^2+2x-24=0.

\[x² + 2x - 24 = 0\]

\[D = 2^{2} - 4 \cdot 1 \cdot ( - 24) =\]

\[= 4 + 96 = 100\]

\[x_{1} = \frac{- 2 + \sqrt{100}}{2 \cdot 1} = \frac{- 2 + 10}{2} =\]

\[= \frac{8}{2} = 4\]

\[x_{2} = \frac{- 2 - \sqrt{100}}{2 \cdot 1} = \frac{- 2 - 10}{2} =\]

\[= - \frac{12}{2} = - 6\]

\[Ответ:x = 4;\ x = - 6.\]