\[\frac{9x - 7^{\backslash 2x - 3}}{3x - 2} - \frac{4x - 5^{\backslash 3x - 2}}{2x - 3} = 1\]
\[- 18x + 11 + 9x + 4x - 6 = 0\]
\[- 5x + 5 = 0\]
\[5 \cdot (1 - x) = 0\]
\[1 - x = 0\]
\[x = 1\]
\[Ответ:x = 1.\]