Решите уравнение: (8x-3)/7-(3x+1)/10=2.

\[\frac{8x - 3}{7} - \frac{3x + 1}{10} = 2\ \ \ | \cdot 70\]

\[10 \cdot (8x - 3) - 7 \cdot (3x + 1) = 140\]

\[80x - 30 - 21x - 7 = 140\]

\[59x = 140 + 37\]

\[59x = 177\]

\[x = 3.\]