\[\frac{8}{x - 3} - \frac{10}{x} = 2;\ \ \ x
eq 3;x
eq 0\]
\[8x - 10(x - 3) = 2x(x - 3)\]
\[8x - 10x + 30 = 2x^{2} - 6x\]
\[2x^{2} - 4x - 30 = 0\ \ \ |\ :2\]
\[x^{2} - 2x - 15 = 0\]
\[D_{1} = 1 + 15 = 16\]
\[x_{1} = 1 + 4 = 5;\ \]
\[x_{2} = 1 - 4 = - 3.\]
\[Ответ:\ - 3;5.\]