Решите уравнение: (8x+1)(2x-3)-(4x-2)^2=1.

\[- 6x - 8 = 0\]

\[- 6x = 8\]

\[x = - \frac{8}{6} = - \frac{4}{3}\]

\[x = - 1\frac{1}{3}.\]