Решите уравнение: (6x-1)/4-(3x+1)/3=1/4.

\[\frac{6x - 1}{4} - \frac{3x + 1}{3} = \frac{1}{4}\ \ \ \ | \cdot 12\]

\[3(6x - 1) - 4(3x + 1) = 3\]

\[18x - 3 - 12x - 4 = 3\]

\[6x = 3 + 7\]

\[6x = 10\]

\[x = \frac{10}{6} = \frac{5}{3}\]

\[x = 1\frac{2}{3}.\]