Решите уравнение: (6x^2-x)/(2-12x)=0

\[\frac{6x^{2} - x}{2 - 12x} = 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ОДЗ:\ \ \ \ x \neq \frac{1}{6}\]

\[\frac{x(6x - 1)}{2 \cdot (1 - 6x)} = 0\]

\[\frac{- x(1 - 6x)}{2 \cdot (1 - 6x)} = 0\]

\[- x = 0\]

\[x = 0\]

\[Ответ:\ \ \ \ x = 0.\]