Решите уравнение: 6x^2-5x+1=0.

\[6x^{2} - 5x + 1 = 0\]

\[D = 25 - 24 = 1\]

\[x_{1} = \frac{5 + 1}{12} = \frac{6}{12} = 0,5;\]

\[x_{2} = \frac{5 - 1}{12} = \frac{4}{12} = \frac{1}{3}.\]

\[Ответ:x = \frac{1}{3};\ \ x = 0,5.\]