Решите уравнение: (5x-8)/(x-1)=(14x+12)/(3x+5).

\[(5x - 8)(3x + 5) =\]

\[= (14x + 12)(x - 1)\]

\[15x^{2} + 25x - 24x - 40 =\]

\[= 14x^{2} - 14x + 12x - 12\]

\[x^{2} + 3x - 28 = 0\]

\[x_{1} + x_{2} = - 3;\ \ \ \ x_{1} \cdot x_{2} = - 28\]

\[x_{1} = 4,\ \ x_{2} = - 7\]

\[Ответ:x = 4;\ x = - 7.\]