Решите уравнение: (4x-1)(3x-2)=(6x+1)(2x+3)-4x.

\[(4x - 1)(3x - 2) =\]

\[= (6x + 1)(2x + 3) - 4x\]

\[12x^{2} - 3x - 8x + 2 =\]

\[= 12x^{2} + 2x + 18x + 3 - 4x\]

\[- 11x - 16x = 3 - 2\]

\[- 27x = 1\]

\[x = - \frac{1}{27}.\]