Решите уравнение: (4x+3)^2-3(3-8x)=0.

\[(4x + 3)^{2} - 3 \cdot (3 - 8x) = 0\]

\[16x^{2} + 48x = 0\]

\[16x(x + 3) = 0\]

\[16x = 0\ \ \ \ \ \ \ \ \ \ x + 3 = 0\]

\[x = 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - 3\]

\[Ответ:x = 0;\ x = - 3.\]