Решите уравнение: (4x+3)^2=(3x-2)(4x+1).

\[(4x + 3)^{2} = (3x - 2)(4x + 1)\]

\[16x^{2} + 24x + 9 = 12x^{2} - 8x + 3x - 2\]

\[4x^{2} + 29x + 11 = 0\]

\[D = 841 - 176 = 665\]

\[x_{1,2} = \frac{- 29 \pm \sqrt{665}}{8}.\]

\[Ответ:\ x_{1,2} = \frac{- 29 \pm \sqrt{665}}{8}.\]