Решите уравнение: 49x^3-14x^2+x=0.

\[49x³ - 14x^{2} + x = 0\]

\[x(7x - 1)^{2} = 0\]

\[x = 0\ \ \ или\ \ \ \ 7x = 1\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{1}{7}\]

\[Ответ:x = 0;x = \ \frac{1}{7}.\]