Решите уравнение: (3x-2)^2-(3x-4)(4+3x)=6.

\[(3x - 2)^{2} - (3x - 4)(4 + 3x) = 6\]

\[9x^{2} - 12x + 4 - 9x^{2} + 16 - 6 = 0\]

\[- 12x + 14 = 0\]

\[- 12x = - 14\]

\[x = \frac{14}{12} = \frac{7}{6}\]

\[x = 1\frac{1}{6}.\]