Решите уравнение: (3x-1)^2-8(x+1)^2=(2+x)(2-x).

\[(3x - 1)^{2} - 8(x + 1)^{2} = (2 + x)(x - 2)\]

\[9x^{2} - 6x + 1 - 8x^{2} - 16x - 8 = x^{2} - 4\]

\[- 22x = - 4 + 7\]

\[- 22x = 3\]

\[x = - \frac{3}{22}.\]