Решите уравнение: 3x^2-7x-6=0;

\[\ 3x² - 7x - 6 = 0\]

\[D = b^{2} - 4ac = 49 - 4 \cdot 3 \cdot ( - 6) =\]

\[= 49 + 72 = 121\]

\[x_{1} = \frac{7 + 11}{6} = \frac{18}{6} = 3\]

\[x_{2} = \frac{7 - 11}{6} = - \frac{4}{6} = - \frac{2}{3}\ \]

\[Ответ:\ \ x = 3\ \ и\ \ x = - \frac{2}{3}.\]