\[3x^{2} + 7x + 2 = 0\]
\[D = 49 - 48 = 1\]
\[x_{1} = \frac{- 7 + 1}{6} = - 1;\ \ \ \]
\[x_{2} = \frac{- 7 - 1}{6} = - \frac{8}{6} = - \frac{4}{3} = - 1\frac{1}{3}.\]
\[Ответ:x = - 1\frac{1}{3};\ \ x = - 1.\]