\[\frac{3^{\backslash x}}{x^{2} + 2} = \frac{1^{\backslash x^{2} + 2}}{x};\ \ x \neq 0\]
\[3x = x^{2} + 2\]
\[x^{2} - 3x + 2 = 0\]
\[x_{1} + x_{2} = 3;\ \ x_{1} \cdot x_{2} = 2\]
\[x_{1} = 1;\ \ \ x_{2} = 2.\]
\[Ответ:x = 1;x = 2.\]