Решите уравнение: 3x^2+13x-10=0.

\[3x^{2} + 13x - 10 = 0\]

\[D = 169 + 120 = 289 = 17^{2}\]

\[x_{1} = \frac{- 13 + 17}{6} = \frac{4}{6} = \frac{2}{3};\ \]

\[x_{2} = \frac{- 13 - 17}{6} = - 5.\]

\[Ответ:x = - 5;x = \frac{2}{3}.\]