Решите уравнение: (2y-5)/(y+5)=(3y+21)/(2y-1).

\[\frac{2y - 5}{y + 5} = \frac{3y + 21}{2y - 1}\]

\[ОДЗ:\ \ y + 5 \neq 0;\ \ y \neq - 5\]

\[2y - 1 \neq 0;\ \ y \neq 0,5\]

\[\frac{2y - 5}{y + 5} - \frac{3y + 21}{2y - 1} = 0\]

\[y^{2} - 48y - 100 = 0\]

\[y_{1} + y_{2} = 48\]

\[y_{1} \cdot y_{2} = - 100 \Longrightarrow y_{1} = 50;\ \ \]

\[y_{2} = - 2\]

\[Ответ:y = 50\ \ и\ \ y = - 2.\]