Решите уравнение: (2x-5)^2-(2x-3)(2x+3)=0.

\[(2x - 5)^{2} - (2x - 3)(2x + 3) = 0\]

\[4x^{2} - 20x + 25 - 4x^{2} + 9 = 0\]

\[- 20x + 34 = 0\]

\[- 20x = - 34\]

\[x = \frac{34}{20} = \frac{17}{10} = 1,7.\]

\[Ответ:x = 1,7.\]