Решите уравнение: 1/(x-5)-2/(x^2+5x)=20/(x^3-25x).

\[\frac{1}{x - 5} - \frac{2}{x^{2} + 5x} = \frac{20}{x^{3} - 25x}\]

\[x(x + 5) - 2 \cdot (x - 5) - 20 = 0\]

\[x^{2} + 5x - 2x + 10 - 20 = 0\]

\[x² + 3x - 10 = 0\]

\[x_{1} + x_{2} = - 3;\ \ \ \ x_{1} \cdot x_{2} = - 10\]

\[x_{1} = 2;\ \ \ \ \]

\[x_{2} = - 5\ (не\ подходит).\]

\[Ответ:x = 2.\]