Решите уравнение: 12-(4-x)^2=x(3-x).

\[12 - (4 - x)^{2} = x(3 - x)\]

\[12 - 16 + 8x - x^{2} = 3x - x^{2}\]

\[8x - 3x = 4\]

\[5x = 4\]

\[x = \frac{4}{5}\]

\[x = 0,8.\]