Решите систему уравнений: x+3y=11; 2x+y^2=14.

\[22 - 6y + y^{2} - 14 = 0\]

\[y^{2} - 6y + 8 = 0\]

\[D_{1} = 9 - 8 = 1\]

\[y_{1} = 3 + 1 = 4;\ \ \ \]

\[y_{2} = 3 - 1 = 2.\]

\[\left\{ \begin{matrix} y = 4\ \ \ \\ x = - 1 \\ \end{matrix} \right.\ \ \ \ \ \ или\ \ \ \ \left\{ \begin{matrix} y = 2 \\ x = 5 \\ \end{matrix} \right.\ \]

\[Ответ:( - 1;4);\ \ (5;2).\]