Решите систему уравнений: 9x^2+6xy+y^2=16; 3x^2+xy=8.

\[3x^{2} + x(4 - 3x) = 8\]

\[3x^{2} + 4x - 3x^{2} = 8\]

\[4x = 8\]

\[x = 2.\]

\[x_{1} = 2 \Longrightarrow y_{1} = 4 - 3 \cdot 2 =\]

\[= 4 - 6 = - 2.\]

\[3x^{2} + x( - 4 - 3x) = 8\]

\[3x^{2} - 4x - 3x^{2} = 8\]

\[- 4x = 8\]

\[x = - 2.\]

\[x_{2} = - 2 \Longrightarrow \text{\ \ \ }\]

\[\Longrightarrow \text{\ \ }y_{2} = - 4 - 3 \bullet ( - 2) =\]

\[= - 4 + 6 = 2.\]

\[Ответ:(2;\ - 2),\ \ \ ( - 2;2).\]