Решите систему уравнений: x+2y+3z=4; 3x-2y-z=-6; 2x-3y+2z=-3.

\[*\ \ \ \ y = 7 - 6 \cdot ( - 1 - 2x) =\]

\[= 7 + 6 + 12x = 12x + 13\]

\[**\ \ 2x + 3 \cdot (12x + 13) = 1\]

\[2x + 36x + 39 = 1\ \ \ \ \ \]

\[38x = - 38\]

\[\left\{ \begin{matrix} x = - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ z = - 1 - 2 \cdot ( - 1) \\ y = 7 - 6z\ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ }\]

\[\left\{ \begin{matrix} x = - 1 \\ z = 1\ \ \ \ \\ y = 1\ \ \ \ \\ \end{matrix} \Longrightarrow \ \ \ \ \ ( - 1;1;1) \right.\ \]