Решите систему уравнений: 10(a+3)=-1-6b, 6(b+3)=8-3a.

\[\left\{ \begin{matrix} 10 \cdot (a + 3) = - 1 - 6b \\ 6 \cdot (b + 3) = 8 - 3a\ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 10a + 30 = - 1 - 6b \\ 6b + 18 = 8 - 3a\ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix} 10a + 6b = - 31 \\ 6b + 3a = - 10\ \\ \end{matrix} - \right.\ \]

\[\left\{ \begin{matrix} 7a = - 21\ \ \ \ \ \ \ \ \ \ \\ b = \frac{- 31 - 10a}{b} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} a = - 3 \\ b = - \frac{1}{6} \\ \end{matrix} \right.\ \]

\[Ответ:\left( - 3;\ - \frac{1}{6} \right).\]