Решите систему неравенств: x^2-8x+15>=0; (4-x)/2<0.

\[x^{2} - 8x - 15 = (x - 3)(x - 5)\]

\[x_{1} + x_{2} = 8;\ \ \ x_{1} \cdot x_{2} = 15\]

\[x_{1} = 3;\ \ \ x_{2} = 5.\]

\[(x - 3)(x - 5) \geq 0\]

\[x \leq 3;\ \ x \geq 5.\]

\[Ответ:x \geq 5.\]