Решите систему неравенств: x^2-5x-14<=0; 3x+6<=0.

\[\left\{ \begin{matrix} x² - 5x - 14 \leq 0\ \ (1) \\ 3x + 6 \leq 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ (2) \\ \end{matrix} \right.\ \]

\[(1)\ x_{1} + x_{2} = 5,\ \ \ x_{1} + x_{2} = - 14\]

\[x_{1} = 7,\ \ x_{2} = - 2\]

\[(2)\ x \leq - 2\]

\[Ответ:\ \left\{ - 2 \right\}.\]