Решите систему неравенств 4-6x<1; 3,6+x>3,8

\[\ \left\{ \begin{matrix} 4 - 6x < 1\ \ \ \ \\ 3,6 + x > 3,8 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\left\{ \begin{matrix} - 6x < - 3 \\ x > 0,2\ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix} x > 0,5 \\ x > 0,2 \\ \end{matrix} \right.\ \]

\[Ответ:x \in (0,5;\ + \infty)\text{.\ }\]

\[\ |5x + 1| = 6\]

\[5x + 1 = - 6\]

\[5x = - 7\]

\[x = - \frac{7}{5}\]

\[x = - 1,4\]

\[5x + 1 = 6\]

\[5x = 5\]

\[x = 1\]

\[Ответ:\ \ x = - 1,4\ \ и\ \ x = 1.\]