Решите систему неравенств: 2x^2+13x-7<=0; 15-3x<=0.

Ответ:

\[\left\{ \begin{matrix} 2x^{2} + 13x - 7 \leq 0\ \ \ \ \ \ \ \ \ \\ 15 - 3x \leq 0,\ \ x \geq 5\ \\ \end{matrix}\text{\ \ \ \ \ \ \ } \right.\ \]

\[2x^{2} + 13x - 7 = 0\]

\[D = 169 + 56 = 225\]

\[x_{1} = \frac{- 13 + 15}{4} = 0,5\]

\[x_{2} = \frac{- 13 - 15}{4} = - 7\]

\[Ответ:\ \varnothing.\]