Решите неравенство (x-1)/(x+5)<=3.

\[\frac{x - 1}{x + 5} \leq 3^{\backslash x + 5}\ \]

\[x - 1 - 3x - 15 = - 2x - 16\]

\[- \frac{2x + 16}{x + 5} \leq 3\]

\[x = - 8;\ \ \ x = - 5.\]

\[Ответ:x \in ( - \infty; - 8\rbrack \cup ( - 5; + \infty).\]