Решите неравенство: (x^3-2x^2-9x+18)/(2-x)>=0.

\[\frac{x^{3} - 2x^{2} - 9x + 18}{2 - x} \geq 0\]

\[\frac{x^{2}(x - 2) - 9 \cdot (x - 2)}{- (x - 2)} \geq 0\]

\[\frac{(x - 2)(x^{2} - 9)}{x - 2} \leq 0\]

\[\frac{(x - 2)(x - 3)(x + 3)}{x - 2} \leq 0\]

\[Ответ:\lbrack - 3;2) \cup (2;3\rbrack.\]