Решите неравенство: x^2/(x-2)>(-4)/(2-x).

\[\frac{x^{2}}{x - 2} > \frac{- 4}{2 - x}\]

\[\frac{x^{2}}{x - 2} > \frac{4}{x - 2}\]

\[\frac{x^{2} - 4}{x - 2} > 0\]

\[\frac{(x - 2)(x + 2)}{x - 2} > 0\]

\[Ответ:( - 2;2) \cup (2; + \infty).\]