Решите неравенство: x^2-7x+6>0.

\[x^{2} - 7x + 6 > 0\]

\[D = ( - 7)^{2} - 4 \cdot 1 \cdot 6 =\]

\[= 49 - 24 = 25\]

\[x_{1} = \frac{7 + \sqrt{25}}{2 \cdot 1} = \frac{7 + 5}{2} = \frac{12}{2} = 6;\ \ \ \ \ \]

\[x_{2} = \frac{7 - \sqrt{25}}{2 \cdot 1} = \frac{7 - 5}{2} = \frac{2}{2} = 1\]

\[Ответ:( - \infty;1) \cup (6; + \infty).\]