Решите неравенство: (x+2)(x^2-64)/(x^2+15)<=0.

Ответ:

\[\frac{(x + 2)\left( x^{2} - 64 \right)}{x^{2} + 15} \leq 0\]

\[x^{2} + 15 \geq 0\ при\ любом\ x:\]

\[(x + 8)(x + 2)(x - 8) \leq 0\]

\[x \leq - 8;\ - 2 \leq x \leq 8.\]