Решите неравенство: 9x^2-6x+1<=0.

\[9x² - 6x + 1 \leq 0\]

\[(3x - 1)^{2} \leq 0\]

\[3x - 1 = 0\]

\[x = \frac{1}{3}\]

\[Ответ:\ \left\{ \frac{1}{3} \right\}.\]