Решите неравенство: (8x+1)/3<=(7x-5)/4.

\[\frac{8x + 1}{3} \leq \frac{7x - 5}{4}\ \ \ \ \ | \cdot 12\]

\[4(8x + 1) \leq 3(7x - 5)\]

\[32x + 4 \leq 21x - 15\]

\[11x \leq - 19\]

\[x \leq - \frac{19}{11}\]

\[x \leq - 1\frac{8}{11}.\]