Решите неравенство 3x^2-5x-22>0.

\[3x^{2} - 5x - 2 > 0\]

\[D = 25 + 24 = 49\]

\[x_{1} = \frac{5 + 7}{6} = 2;\ \ \ \]

\[x_{2} = \frac{5 - 7}{6} = - \frac{2}{6} = - \frac{1}{3}.\]

\[3 \cdot \left( x + \frac{1}{3} \right)(x - 2) > 0\]

\[Ответ:x \in \left( - \infty; - \frac{1}{3} \right) \cup (2; + \infty).\]