Решите неравенство: (3x+4)/(x+1)<2.

\[\frac{3x + 4}{x + 1} < 2\]

\[\frac{3x + 4}{x + 1} - 2^{\backslash x + 1} < 0\]

\[\frac{3x + 4 - 2 \cdot (x + 1)}{x + 1} < 0\]

\[\frac{3x + 4 - 2x - 2}{x + 1} < 0\]

\[\frac{x + 2}{x + 1} < 0\ \]

\[Ответ:( - 2;\ - 1).\]