Решите неравенство: 3(x+1)<=x+5.

\[3(x + 1) \leq x + 5\]

\[3x + 3 \leq x + 5\]

\[3x - x \leq 5 - 3\]

\[2x \leq 2\]

\[x \leq 1.\]

\[Ответ:x \in ( - \infty;1\rbrack.\]