Решите неравенство: 2<(4x+3)/3<=3.

\[2 < \frac{4x + 3}{3} \leq 3\]

\[6 < 4x + 3 \leq 9\]

\[3 < 4x \leq 6\]

\[\frac{3}{4} < x \leq 1,5\]

\[Ответ:\left( \frac{3}{4};1,5 \right\rbrack.\]