Вопрос:

Решите графически систему уравнений y=x^2-4x; 2x-y=8.

Ответ:

\[\left\{ \begin{matrix} y = x² - 4x \\ 2x - y = 8\ \ \\ \end{matrix} \right.\ \Longrightarrow \left\{ \begin{matrix} y = x² - 4x \\ y = 2x - 8\ \ \\ \end{matrix} \right.\ \]

\[y = x^{2} - 4x\]

\[x_{0} = \frac{4}{2} = 2;\]

\[y_{0} = 4 - 8 = - 4\]

\[(2;\ - 4).\]

\[x\] \[0\] \[1\]
\[y\] \[0\] \[- 3\]

\[y = 2x - 8\]

\[x\] \[2\] \[3\]
\[y\] \[- 4\] \[- 2\]

\[Ответ:(4;0);\ \ (2;\ - 4).\]


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