Решите двойное неравенство: -1<= (6+2x)/4<=0.

\[- 1 \leq \frac{6 + 2x}{4} \leq 0\]

\[- 4 \leq 6 + 2x \leq 0\]

\[- 10 \leq 2x \leq - 6\]

\[- 5 \leq x \leq - 3\ \]

\[Ответ:x \in \lbrack - 5; - 3\rbrack.\]