\[\left\{ \begin{matrix} 6(x + 1) < - (10 + 2x) \\ \frac{x + 4}{3} \leq \frac{2x - 3}{4}\ \ \ \ \ \ | \cdot 12 \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} 6x + 6 < - 10 - 2x \\ 4x + 16 \leq 6x - 9\ \ \ \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} 8x < - 16\text{\ \ \ } \\ - 2x \leq - 25 \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} x < - 2\ \ \ \\ x \geq 12,5 \\ \end{matrix} \right.\ \]
\[нет\ решений.\]
\[Ответ:нет\ решений.\]