Решить систему неравенств: 5(x+1)<=3(x+3)+1; (2x-1)/7>=(x+1)/2.

\[\left\{ \begin{matrix} 5(x + 1) \leq 3(x + 3) + 1 \\ \frac{2x - 1}{7} \geq \frac{x + 1}{2}\ \ \ \ \ \ \ | \cdot 14\ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 5x + 5 \leq 3x + 9 + 1 \\ 4x - 2 \geq 7x + 7\ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 2x \leq 5\ \ \ \ \\ - 3x \geq 9 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} x \leq 2,5 \\ x \leq - 3 \\ \end{matrix} \right.\ \]

\[x \leq - 3.\]

\[Ответ:x \leq - 3.\]