Решить неравенства методом интервалов: (16-x^2)/((5+2x)(8-x))>0.

\[\frac{\left( 16 - x^{2} \right)}{(5 + 2x)(8 - x)} > 0\]

\[\frac{- (x^{2} - 16)}{- 2(x + 2,5)(x - 8)} > 0\]

\[\frac{(x + 4)(x - 4)}{2(x + 2,5)(x - 8)} > 0\]

\[x < - 4;\ - 2,5 < x < 4;x > 8.\]

\[Ответ:x < - 4;x > 8;\]

\[- 2,5 < x < 4.\]